If $C$ be the capacitance and $V$ be the electric potential, then the dimensional formula of $C{V}^2$ is

• A

  $\left[{\mathrm{M}\mathrm{L}}^{-3}\mathrm{T}\mathrm{A}\right]$
• B

  $\left[{\mathrm{K}}^0{\mathrm{L}\mathrm{T}}^{-2}{\mathrm{A}}^0\right]$
• C

  $\left[{\mathrm{M}\mathrm{L}}^1{\mathrm{T}}^{-2}{\mathrm{A}}^{-1}\right]$
• Correct answer
  D

  $\left[{\mathrm{M}\mathrm{L}}^2{\mathrm{T}}^{-2}{\mathrm{A}}^0\right]$

Hence, the correct answer is option: 'D'.