If $\overline{\mathrm{a}}=\overline{\mathrm{i}}+p \overline{\mathrm{j}}-3 \overline{\mathrm{k}}, \overline{\mathrm{b}}=p \overline{\mathrm{i}}-3 \overline{\mathrm{j}}+\overline{\mathrm{k}}, \overline{\mathrm{c}}=-3 \overline{\mathrm{i}}+\overline{\mathrm{j}}+2 \overline{\mathrm{k}}$ are three vectors such that $|\overline{\mathrm{a}} \times \overline{\mathrm{b}}|=|\overline{\mathrm{a}} \times \overline{\mathrm{c}}|$, then $\mathrm{p}=$

• A

  $-2$
• B

  $-1$
• C

  $1$
• Correct answer
  D

  $2$

Hence, the correct answer is option: 'D'.