Q98 / 160 · TS EAMCET 2025 (02 May Shift 1) · Mathematics
If $\mathrm{A}(0,3,4), \mathrm{B}(1,5,6), \mathrm{C}(-2,0,-2)$ are the vertices of a triangle ABC and the bisector of angle A meets the side BC at D, then $\mathrm{AD}=$
- A$\frac{\sqrt{21}}{5}$
- Correct answerB$\frac{\sqrt{42}}{10}$
- C$10$
- D$4$
Hence, the correct answer is option: 'B'.