Q48 / 160 · AP EAMCET 2025 (23 MAY SHIFT 1) · Mathematics
If $1, \omega, \omega^2$ are the cube roots of unity, then
$1\left(2+\frac{1}{\omega}\right)\left(2+\frac{1}{\omega^2}\right)+2\left(3+\frac{1}{\omega}\right)\left(3+\frac{1}{\omega^2}\right)+3\left(4+\frac{1}{\omega}\right)\left(4+\frac{1}{\omega^2}\right)+\ldots 10 \text { terms }=$
- A$3080$
- Correct answerB$3465$
- C$3175$
- D$3715$
Hence, the correct answer is option: 'B'.