Q48 / 160 · AP EAMCET 2025 (23 MAY SHIFT 1) · Mathematics

If $1, \omega, \omega^2$ are the cube roots of unity, then $1\left(2+\frac{1}{\omega}\right)\left(2+\frac{1}{\omega^2}\right)+2\left(3+\frac{1}{\omega}\right)\left(3+\frac{1}{\omega^2}\right)+3\left(4+\frac{1}{\omega}\right)\left(4+\frac{1}{\omega^2}\right)+\ldots 10 \text { terms }=$

  • A
    $3080$
  • Correct answer
    B
    $3465$
  • C
    $3175$
  • D
    $3715$

Hence, the correct answer is option: 'B'.

Relevant Questions