If $\bar{u}, \bar{v}, \bar{w}$ are non coplanar vectors and $p, q$ are real numbers, then the equality $\left[\begin{array}{lll}3 \overline{\mathrm{u}} & \mathrm{p} \overline{\mathrm{v}} & \mathrm{p} \overline{\mathrm{w}}\end{array}\right]-\left[\begin{array}{lll}\mathrm{p} \overline{\mathrm{v}} & \overline{\mathrm{w}} & \mathrm{q} \overline{\mathrm{u}}\end{array}\right]-\left[\begin{array}{lll}2 \overline{\mathrm{w}} & \mathrm{q} \overline{\mathrm{v}} & \mathrm{q} \overline{\mathrm{u}}\end{array}\right]=0$ holds for

• Correct answer
  A

  exactly one ordered pair of (p,q)
• B

  exactly two ordered pairs of (p,q)
• C

  all ordered pairs of (p,q)
• D

  no ordered pair of (p,q)

Hence, the correct answer is option: 'A'.