Q113 / 200 · Manipal (MET) 2010 · Mathematics
If $\left(m_i, \frac{1}{m_i}\right)$ are four distinct points on a circle, then
- Correct answerA$m_1 m_2 m_3 m_4=1$
- B$m_1 m_2 m_3 m_4=-1$
- C$m_1 m_2 m_3 m_4=\frac{1}{2}$
- D$\frac{1}{m_1}+\frac{1}{m_2}+\frac{1}{m_3}+\frac{1}{m_4}=\frac{1}{4}$
Solution
Let the points $\left(m_i, \frac{1}{m_i}\right), i=1,2,3,4$ lie on the
circle $x^2+y^2+2 g x+2 f y+c=0$
Then,
$\Rightarrow m_i^2+\frac{1}{m_i^2}+2 g m_i+\frac{2 f}{m_i}+c=0, i=1,2,3,4$
$\Rightarrow m_i^4+2 g m_i^3+c m_i^2+2 f m_i+1=0$, $i=1,2,3,4$
$\Rightarrow m_1, m_2, m_3$ and $m_4$ are the roots of the equatión
$m^4+2 g m^3+c m^2+2 f m+1=0$
$\Rightarrow m_1 m_2 m_3 m_4=\frac{1}{1}=1$
Hence, the correct answer is option: 'A'.