Q225 / 270 · NDA 2017 (Phase 2) · Mathematics
If $\lim _{x \rightarrow \frac{\pi}{2}} \frac{\sin x}{x}=l$ and $\lim _{x \rightarrow \infty} \frac{\cos x}{x}=m$, then which one of the following is correct?
- A$l=1, \mathrm{~m}=1$
- B$l=\frac{2}{\pi}, \mathrm{~m}=\infty$
- Correct answerC$l=\frac{2}{\pi}, \mathrm{~m}=0$
- D$l=1, \mathrm{~m}=\infty$
Solution
$\begin{aligned} & \lim _{x \rightarrow \frac{\pi}{2}} \frac{\sin x}{x}=l \text { and } \lim _{x \rightarrow \infty} \frac{\cos x}{x}=m \\ & \lim _{x \rightarrow \frac{\pi}{2}} \frac{\sin x}{x}=\frac{1}{\frac{\pi}{2}}=\frac{2}{\pi} ; \lim _{x \rightarrow \infty} \frac{\cos x}{x}=0\end{aligned}$
$\therefore l=\frac{2}{\pi}, \mathrm{~m}=0$
Hence, the correct answer is option: 'C'.