If A= (cos 12^°-cos 36^° ) (sin 96^°+sin 24^° ) and B= (sin 60^°-sin 12^° ) (cos 48^°-cos 72^° ) , then what is A/B equal to?

Question

MARKS Content Team · Accepted Answer

Correct answer: (C) 1. Given A= (cos 12^°-cos 36^° ) (sin 96^°+sin 24^° ) B= (sin 60^°-sin 12^° ) (cos 48^°-cos 72^° ) A/B=frac [2 sin 24^° sin 12^° ] [2 sin 60^° cos 36^° ] [2 cos 36^° sin 24^° ] [2 sin 60^° sin 12^° ] ⇒ A/B=1

If $A=\left(\cos 12^{\circ}-\cos 36^{\circ}\right)\left(\sin 96^{\circ}+\sin 24^{\circ}\right)$ and $\mathrm{B}=\left(\sin 60^{\circ}-\sin 12^{\circ}\right)\left(\cos 48^{\circ}-\cos 72^{\circ}\right)$, then what is $\frac{\mathrm{A}}{\mathrm{B}}$ equal to?

Solution

Relevant Questions