Q203 / 270 · NDA 2010 (Phase 2) · Mathematics
If $x=\cos (2 t)$ and $y=\sin ^2 t$, then what is $\frac{d^2 y}{d x^2}$ equal to?
- Correct answerA0
- B$\sin (2 t)$
- C$-\cos (2 t)$
- D$-1 / 2$
Solution
$\begin{aligned} & x=\cos ^{(2 t)} \text { and } y=\sin ^2 t \\ & \therefore \frac{d x}{d t}=-2 \sin 2 t \text { and } \frac{d y}{d t}=2 \sin t \cdot \cos t \\ & \therefore \frac{d y}{d x}=\frac{2 \sin t \cdot \cos t}{-4 \sin t \cdot \cos t}=-\frac{1}{2} \\ & \therefore \frac{d^2 y}{d x^2}=0\end{aligned}$
Hence, the correct answer is option: 'A'.