Q72 / 155 · WBJEE 2024 · Mathematics

If $A=\left(\begin{array}{cc}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right)$ and $\theta=\frac{2 \pi}{7}$, then $A^{100}=A \times A \times \ldots .(100$ times $)$ is equal to

  • Correct answer
    A
    $\left(\begin{array}{cc}\cos 2 \theta & -\sin 2 \theta \\ \sin 2 \theta & \cos 2 \theta\end{array}\right)$
  • B
    $\left(\begin{array}{cc}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right)$
  • C
    $\left(\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right)$
  • D
    $\left(\begin{array}{cc}0 & -1 \\ 1 & 0\end{array}\right)$

Solution

Hint : $\because A^{100}=\left[\begin{array}{cc}\cos 100 \theta & -\cos 100 \theta \\ \sin 100 \theta & \cos 100 \theta\end{array}\right]$ As $\theta=\frac{2 \pi}{7}$ $A^{100}=\left[\begin{array}{cc} \cos \frac{200 \pi}{7} & -\sin \frac{200 \pi}{7} \\ \sin \frac{200 \pi}{7} & \cos \frac{200 \pi}{7} \end{array}\right]=A^2$

Hence, the correct answer is option: 'A'.

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