Q72 / 155 · WBJEE 2024 · Mathematics
If $A=\left(\begin{array}{cc}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right)$ and $\theta=\frac{2 \pi}{7}$, then $A^{100}=A \times A \times \ldots .(100$ times $)$ is equal to
- Correct answerA$\left(\begin{array}{cc}\cos 2 \theta & -\sin 2 \theta \\ \sin 2 \theta & \cos 2 \theta\end{array}\right)$
- B$\left(\begin{array}{cc}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right)$
- C$\left(\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right)$
- D$\left(\begin{array}{cc}0 & -1 \\ 1 & 0\end{array}\right)$
Solution
Hint : $\because A^{100}=\left[\begin{array}{cc}\cos 100 \theta & -\cos 100 \theta \\ \sin 100 \theta & \cos 100 \theta\end{array}\right]$
As $\theta=\frac{2 \pi}{7}$
$A^{100}=\left[\begin{array}{cc}
\cos \frac{200 \pi}{7} & -\sin \frac{200 \pi}{7} \\
\sin \frac{200 \pi}{7} & \cos \frac{200 \pi}{7}
\end{array}\right]=A^2$
Hence, the correct answer is option: 'A'.