If $3 \sin (\alpha-\beta)=5 \cos (\alpha+\beta)$ and $\alpha+\beta \neq \frac{\pi}{2}$, then $\frac{\tan \left(\frac{\pi}{4}-\alpha\right)}{\tan \left(\frac{\pi}{4}-\beta\right)}=$

• A

  $0$
• B

  $-4$
• Correct answer
  C

  $-\frac{1}{4}$
• D

  $\frac{1}{2}$

Hence, the correct answer is option: 'C'.