Q60 / 160 · AP EAMCET 2025 (21 MAY SHIFT 1) · Mathematics
If $630^{\circ} < \theta < 810^{\circ}$ and $\tan \theta=-\frac{7}{24}$, then $\cos \left(\frac{\theta}{4}\right)=$
- Correct answerA$-\sqrt{\frac{7+5 \sqrt{2}}{10 \sqrt{2}}}$
- B$\sqrt{\frac{7+5 \sqrt{2}}{2 \sqrt{2}}}$
- C$-\sqrt{\frac{5 \sqrt{2}-7}{10 \sqrt{2}}}$
- D$\sqrt{\frac{5 \sqrt{2}-7}{2 \sqrt{2}}}$
Hence, the correct answer is option: 'A'.