Q60 / 160 · AP EAMCET 2025 (21 MAY SHIFT 1) · Mathematics

If $630^{\circ} < \theta < 810^{\circ}$ and $\tan \theta=-\frac{7}{24}$, then $\cos \left(\frac{\theta}{4}\right)=$

  • Correct answer
    A
    $-\sqrt{\frac{7+5 \sqrt{2}}{10 \sqrt{2}}}$
  • B
    $\sqrt{\frac{7+5 \sqrt{2}}{2 \sqrt{2}}}$
  • C
    $-\sqrt{\frac{5 \sqrt{2}-7}{10 \sqrt{2}}}$
  • D
    $\sqrt{\frac{5 \sqrt{2}-7}{2 \sqrt{2}}}$

Hence, the correct answer is option: 'A'.

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