If e^i t=cos t+i sin t and e^-i t=cos t-i sin t then cos h (x+i y)-cosh (x-i y)=

Question

MARKS Content Team · Accepted Answer

Correct answer: (D) 2 i sin h x sin y. sin θ · cos h(x+i y)=cosh x cos h(i y)+sinh x sin h(i y) and cos h(x-i y)=cosh x · cosh (i y)-sinh x · sinh (i y) now cos h(x+i y)-cos h(x-i y)=2 sin h(x) sin h(i y) =2 i sin h(x) sin y

If $e^{i t}=\cos t+i \sin t$ and $e^{-i t}=\cos t-i \sin t$ then $\cos \mathrm{h}$ $(x+i y)-\cosh (x-i y)=$

Solution

Relevant Questions