Q138 / 225 · JEE Main 2003 · Mathematics
If $A=\left[\begin{array}{ll}a & b \\ b & a\end{array}\right]$ and $A_2=\left[\begin{array}{ll}\alpha & \beta \\ \beta & \alpha\end{array}\right]$, then
- A$\alpha=2 a b, \beta=a^2+b^2$
- B$\alpha=\mathrm{a}_2+\mathrm{b}_2, \beta=\mathrm{ab}$
- Correct answerC$\alpha=a^2+b^2, \beta=2 a b$
- D$\alpha=a^2+b^2, \beta=a^2-b^2$
Solution
$A^2=\left[\begin{array}{ll}\alpha & \beta \\ \beta & \alpha\end{array}\right]=\left[\begin{array}{ll}a & b \\ b & a\end{array}\right]\left[\begin{array}{ll}a & b \\ b & a\end{array}\right]$
$\alpha=a^2+b^2 ; \beta=2 a b$
Hence, the correct answer is option: 'C'.