If $\overrightarrow{\mathrm{L}}$ and $\overrightarrow{\mathrm{P}}$ represent the angular momentum and linear momentum respectively of a particle of mass ' m ' having position vector $\overrightarrow{\mathrm{r}}=\mathrm{a}(\hat{\mathrm{i}} \cos \omega \mathrm{t}+\hat{\mathrm{j}} \sin \omega \mathrm{t})$. The direction of force is

• Correct answer
  A

  Opposite to the direction of $\vec{r}$
• B

  Opposite to the direction of $\overrightarrow{\mathrm{L}}$
• C

  Opposite to the direction of $\vec{P}$
• D

  Opposite to the direction of $\overrightarrow{\mathrm{L}} \times \overrightarrow{\mathrm{P}}$

Hence, the correct answer is option: 'A'.