If $x=\frac{\mathrm{t}^2}{1+\mathrm{t}^5}, y=\frac{2 \mathrm{t}^3}{1+\mathrm{t}^5}$ and $\mathrm{t} \neq-1$ is a parameter then $\frac{d y}{d x}=$

• A

  $\frac{2\left(3+2 t^5\right)}{\left(2-3 t^5\right)}$
• Correct answer
  B

  $\frac{2 t\left(3-2 t^5\right)}{\left(2-3 t^5\right)}$
• C

  $\frac{2 t\left(3-2 t^5\right)}{\left(2+3 t^5\right)}$
• D

  $\frac{2\left(3+2 t^5\right)}{\left(2+3 t^5\right)}$

Hence, the correct answer is option: 'B'.