Q45 / 160 · AP EAMCET 2023 (15 May Shift 2) · Mathematics
If $\operatorname{det}(\mathrm{AB})=(\operatorname{det} \mathrm{A})(\operatorname{det} \mathrm{B})$ and $\mathrm{A}$ is a non-singular matrix of $\operatorname{order} 3 \times 3$, then $\operatorname{det}(\operatorname{adj} A)=$
- A$\operatorname{det}(\mathrm{A})$
- B$(\operatorname{det}(\mathrm{A}))^{-1}$
- Correct answerC$(\operatorname{det}(\mathrm{A}))^2$
- D$(\operatorname{det}(\mathrm{A}))^3$
Solution
$\begin{aligned} & \text {Since } \operatorname{adj} A=|A| \Rightarrow|\operatorname{adj} A|=|A|^3 \\ & \Rightarrow|\operatorname{adj} A|=|A|^2\end{aligned}$
Hence, the correct answer is option: 'C'.