Q159 / 160 · AP EAMCET 2024 (22 May Shift 2) · Physics

If $R_C$ and $R_B$ are respectively the resistances of in collector and base sides of the circuit, and $\beta$ is the current amplification factor, then the voltage gain of a transistor amplifier in common emitter configuration is

  • A
    $\beta R_C R_B$
  • B
    $\frac{\beta}{R_C R_B}$
  • C
    $\frac{\beta R_B}{R_C}$
  • Correct answer
    D
    $\frac{\beta R_C}{R_B}$

Solution

The voltage gain of a CE configuration transistor is $A_V=\frac{V_O}{V_I}=\frac{V_C}{V_B}=\frac{I_C R_C}{I_B R_B}=\left(\frac{I_C}{I_B}\right)\left(\frac{R_C}{R_B}\right)=\beta \cdot \frac{R_C}{R_B}$

Hence, the correct answer is option: 'D'.

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