Q61 / 160 · AP EAMCET 2011 · Mathematics

If $a, b$ and $n$ are natural numbers, then $a^{2 n-1}+b^{2 n-1}$ is divisible by

  • Correct answer
    A
    $a+b$
  • B
    $a-b$
  • C
    $a^3+b^3$
  • D
    $a^2+b^2$

Solution

Here, we see that $(2 n-1)$ is an odd number $\therefore a^{2 n-1}+b^{2 n-1}$ is divisible by $a+b$.

Hence, the correct answer is option: 'A'.

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