Q153 / 160 · TS EAMCET 2015 · Physics

If $n_e$ and $n_h$ are electron and hole concentrations in an extrinsic semiconductor and $n_i$ is electron concentrations in an intrinsic semiconductor, then

  • A
    $\left(\frac{n_e}{n_h}\right)=n_i$
  • B
    $\left(n_e+n_h\right)=n_i$
  • C
    $\left(n_e-n_h\right)=n_i^2$
  • Correct answer
    D
    $n_e n_h=n_i^2$

Solution

$n_e$ and $n_h$ are electron and hole concentrations in an extrinsic semiconductor and $n_i$ is electron concentration in an intrinsic semiconductor, then $$ n_e n_h=n_i^2 $$

Hence, the correct answer is option: 'D'.

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