Q17 / 225 · JEE Main 2002 · Chemistry
If an endothermic reaction is non- spantaneous at freezing point of water and becomes feasible at its boiling point, then
- A$\Delta \mathrm{H}$ is - ve, $\Delta \mathrm{S}$ is + ve
- Correct answerB$\Delta \mathrm{H}$ and $\Delta \mathrm{S}$ both are $+$ ve
- C$\Delta \mathrm{H}$ and $\Delta \mathrm{S}$ both are $-$ ve
- D$\Delta \mathrm{H}$ is $+$ ve, $\Delta \mathrm{S}$ is $-\mathrm{ve}$
Solution
$\Delta \mathrm{H}$ +ve at low temperature and $\Delta \mathrm{S}$ +ve at low temperature shows that reaction is non spontaneous
At high temperature (boiling point) becomes feasible
Hence, the correct answer is option: 'B'.