Q83 / 199 · NEET 2008 (Mains) · Chemistry

If 'a' stands for the edge length of the cubic systems : simple cubic, body centred cubic and face centred cubic, then the ratio of radii of the spheres in these systems will be respectively

  • A
    $1 a: \sqrt{3} a: \sqrt{2} a$
  • Correct answer
    B
    $\frac{1}{2} a: \frac{\sqrt{3}}{4} a: \frac{1}{2 \sqrt{2}}^a$
  • C
    $\frac{1}{2} a: \sqrt{3} a: \frac{1}{\sqrt{2}} \mathrm{a}$
  • D
    $\frac{1}{2} \mathrm{a}: \frac{\sqrt{3}}{2} \mathrm{a}: \frac{\sqrt{2}}{2} \mathrm{a}$

Solution

For simple cube, $a=2 r$ or $r=\frac{a}{2}$ For BCC, $4 r=\sqrt{3} a$ or $r=\frac{\sqrt{3}}{4} a$ For FCC, $4 r=\sqrt{2} a$ or $r=\frac{a}{2 \sqrt{2}}$ Thus, the ratio is $\frac{1}{2} a: \frac{\sqrt{3}}{4} a: \frac{1}{2 \sqrt{2}} a$

Hence, the correct answer is option: 'B'.

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