If a real valued function $f(x)= \begin{cases}\log (1+[x]), & x \geq 0 \\ \sin ^{-1}[x], & -1 \leq x < 0 \\ k([x]+|x|), & x < -1\end{cases}$ is continuous at $\mathrm{x}=-1$, then $\mathrm{k}=$

• A

  $-\pi / 2$
• B

  $-\pi$
• C

  $\pi$
• Correct answer
  D

  $\pi / 2$

Hence, the correct answer is option: 'D'.