Q143 / 160 · AP EAMCET 2024 (20 May Shift 2) · Physics
If a microscope is placed in air, the minimum separation of two objects seen as distinct is 6 pm . If the same is placed in a medium of refractive index 1.5 , then the minimum separation of the two objects to see as distinct is
- Correct answerA$4 \mu \mathrm{~m}$
- B$6 \mu \mathrm{~m}$
- C$3 \mu \mathrm{~m}$
- D$9 \mu \mathrm{~m}$
Solution
In air, $\mathrm{d}=6 \mu \mathrm{~m}, \mathrm{n}=1.5$
In medium, $\mathrm{d}^{\prime}=\frac{\mathrm{d}}{\mathrm{n}}=\frac{6}{1.5}=4 \mu \mathrm{~m}$
In medium, $\mathrm{d}^{\prime}=\frac{\mathrm{d}}{\mathrm{n}}=\frac{6}{1.5}=4 \mu \mathrm{~m}$
Hence, the correct answer is option: 'A'.