Q32 / 75 · JEE Main 2020 (08 Jan Shift 2) · Mathematics

If a hyperbola passes through the point P10, 16, and it has vertices at ±6, 0, then the equation of the normal to it at P, is.

  • A
    3x+4y=94
  • Correct answer
    B
    2x+5y=100
  • C
    x+2y=42
  • D
    x+3y=58

Solution

Let the equation of hyperbola is x2a2-y2b2=1.

As, vertex is at ±6,0, and it passes through 10, 16,
So, the equation of hyperbola is x236-y2144=1.
Equation of normal to the hyperbola at x1, y1 is a2xx1+b2yy1=a2+b2

Thus, on putting values, equation of normal is 2x+5y=100.

Hence, the correct answer is option: 'B'.

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