If a → , b → , c → be three unit vectors perpendicular to each other, then 2 a → +3 b → +4 c → ⋅ a → × b → +5 b → × c → +6 c → × a → is equal to

Question

MARKS Content Team · Accepted Answer

Correct answer: (D) 32. 2 a → +3 b → +4 c → ⋅ a → × b → +5 b → × c → +6 c → × a → = 10 a → b → c → +18 a → b → c → +4 a → b → c → =32a→ b→ c→=32 as a→ b→ c→=1

If $\vec{a}, \vec{b}, \vec{c}$ be three unit vectors perpendicular to each other, then $|(2 \vec{a} + 3 \vec{b} + 4 \vec{c}) \cdot (\vec{a} \times \vec{b} + 5 \vec{b} \times \vec{c} + 6 \vec{c} \times \vec{a})|$ is equal to

Solution

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