Q95 / 180 · KCET 2018 · Mathematics

If \( A \) and \( B \) are mutually exclusive events, given that
\( \mathrm{P}(\mathrm{A})=\frac{3}{5}, P(B)=\frac{1}{5} \), then \( \mathrm{P}(\mathrm{A} \) or \( \mathrm{B}) \) is

  • Correct answer
    A
    \( 0.8 \)
  • B
    \( 0.6 \)
  • C
    \( 0.4 \)
  • D
    \( 0.2 \)

Solution

Here \( P(A)=\frac{3}{5}, P(B)=\frac{1}{5} \)
For mutually exclusive events \( A \) and \( B \)
\( P(A \) or \( B)=P(A)+P(B) \)
\( \therefore P(A \) or \( B)=\frac{3}{5}+\frac{1}{5}=\frac{4}{5} \)

Hence, the correct answer is option: 'A'.

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