Q154 / 269 · NDA 2025 (Phase 1) · Mathematics
If 5th, 7th and 13th terms of an AP are in GP, then what is the ratio of its first term to its common difference?
- Correct answerA$-3$
- B$-2$
- C$2$
- D$3$
Solution
Let the first term of the AP be $a$ and the common difference be $d$.
The 5th, 7th, and 13th terms of the AP are $a + 4d$, $a + 6d$, and $a + 12d$ respectively.
Since these terms are in GP, the square of the middle term is equal to the product of the other two terms:
$(a + 6d)^2 = (a + 4d)(a + 12d)$
Expanding both sides:
$a^2 + 12ad + 36d^2 = a^2 + 16ad + 48d^2$
Simplifying the equation:
$4ad + 12d^2 = 0$
$4d(a + 3d) = 0$
Assuming $d \neq 0$ for a non-constant AP, we get:
$a + 3d = 0$
$a = -3d$
The ratio of the first term to the common difference is $\dfrac{a}{d} = -3$.
Answer: $-3$
The 5th, 7th, and 13th terms of the AP are $a + 4d$, $a + 6d$, and $a + 12d$ respectively.
Since these terms are in GP, the square of the middle term is equal to the product of the other two terms:
$(a + 6d)^2 = (a + 4d)(a + 12d)$
Expanding both sides:
$a^2 + 12ad + 36d^2 = a^2 + 16ad + 48d^2$
Simplifying the equation:
$4ad + 12d^2 = 0$
$4d(a + 3d) = 0$
Assuming $d \neq 0$ for a non-constant AP, we get:
$a + 3d = 0$
$a = -3d$
The ratio of the first term to the common difference is $\dfrac{a}{d} = -3$.
Answer: $-3$
Hence, the correct answer is option: 'A'.