Q157 / 160 · TS EAMCET 2021 (05 Aug Shift 2) · Physics

If 5 mg of U235 is completely destroyed in an atom bomb, then approximate total energy released is (given that the energy released per fission is 200 MeV)

  • Correct answer
    A
    4×108 J
  • B
    6×109 J
  • C
    5×107 J
  • D
    3×1010 J

Solution

Number of uranium atom is, N=NA235×5×10-3
⇒N=6.022×1023235×5×10-3=1.28×1019

To energy in this fission is, E=N×200 MeV
⇒E=1.28×1019×200×106×1.6×10-19 J
⇒E≈4×108 J

Hence, the correct answer is option: 'A'.

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