Q97 / 150 · MHT CET 2019 (Shift 2) · Mathematics

If $4 {s i n}^{- 1} x + 6 {c o s}^{- 1} x = 3 π$ then x = …..

A
$\frac{1}{\sqrt{2}}$
B
$\frac{1}{2}$
Correct answer
C
0
D
$- \frac{1}{2}$

Solution

We have,

4 {s i n}^{- 1} x + 6 {c o s}^{- 1} x = 3 π

\Rightarrow 4 {s i n}^{- 1} x + 6 (\frac{π}{2} - {s i n}^{- 1} x) = 3 π

\Rightarrow 4 {s i n}^{- 1} x + 3 π - 6 {s i n}^{- 1} x = 3 π

\Rightarrow - 2 {s i n}^{- 1} x = 0 \Rightarrow {s i n}^{- 1} x = 0

\Rightarrow x = \sin (0) = 0

Hence, the correct answer is option: 'C'.

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