If 2+x x x^2 x 2+x x^2 x^2 x 2+x =1/6x-ax-bx-cx-d be an identity in x where a,b,c,d are independent of x, then the value of 13/25abcd is

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MARKS Content Team · Accepted Answer

Correct answer: 24.96. Since, the given equation is an identity in x, putting x=0, we get, 2 0 0 0 2 0 0 0 2 =1/6abcd ⇒abcd=48⇒13/25abcd=(13×48)/25=24.96

If $|\begin{matrix} 2 + x & x & x^{2} \\ x & 2 + x & x^{2} \\ x^{2} & x & 2 + x \end{matrix}| = \frac{1}{6} (x - a) (x - b) (x - c) (x - d)$ be an identity in $x$ where $a, b, c, d$ are independent of $x,$ then the value of $\frac{13}{25} a b c d$ is

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More Determinants Questions

If 2+xxx2x2+xx2x2x2+x=16x-ax-bx-cx-d be an identity in x where a,b,c,d are independent of x, then the value of 1325abcd is

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More Determinants Questions

If $|\begin{matrix} 2 + x & x & x^{2} \\ x & 2 + x & x^{2} \\ x^{2} & x & 2 + x \end{matrix}| = \frac{1}{6} (x - a) (x - b) (x - c) (x - d)$ be an identity in $x$ where $a, b, c, d$ are independent of $x,$ then the value of $\frac{13}{25} a b c d$ is