Q46 / 160 · NTA Abhyas (JEE Main) 2020 · Physics · Thermodynamics

If 2 moles of diatomic gas and 1 mole of monatomic gas are mixed, then the ratio of specific heats for the mixture is

  • A
    7 3
  • B
    5 4
  • Correct answer
    C
    19 13
  • D
    15 19

Solution

μ 1 = 1 ,  γ 1 =5 / 3  (for monatomic gas) and μ 2 = 2 , γ 2 = 7 / 5  (for diatomic gas).

Form formula

    γ mixture = μ 1 γ 1 γ 1 - 1 + μ 2 γ 2 γ 2 - 1 μ 1 γ 1 - 1 + μ 2 γ 2 - 1

               = 1 × 5 3 5 3 - 1 + 2 × 7 5 7 5 - 1 1 5 3 - 1 + 2 7 5 - 1 = 5 3 + 7 3 2 + 5 = 1 9 1 3

Hence, the correct answer is option: 'C'.

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