If $2^{{\mathrm{a}}_1},\mathrm{ }{2}^{{\mathrm{a}}_2}, 2^{{\mathrm{a}}_3}.....\mathrm{ }{2}^{{\mathrm{a}}_{\mathrm{r}}}$ are in geometric progression, then $\left|\begin{array}{lll}{\mathrm{a}}_1& {\mathrm{a}}_2& {\mathrm{a}}_3\\ {\mathrm{a}}_{\mathrm{n}+1}& {\mathrm{a}}_{\mathrm{n}+2}& {\mathrm{a}}_{\mathrm{n}+3}\\ {\mathrm{a}}_{2\mathrm{n}+1}& {\mathrm{a}}_{2\mathrm{n}+2}& {\mathrm{a}}_{2\mathrm{n}+3}\end{array}\right|$ is equal to

• A

  $2^5$
• B

  $2^3$
• Correct answer
  C

  $0$
• D

  None of these

Hence, the correct answer is option: 'C'.