If ∫033x^2-4x+2dx=k, then a root of 3x^2-4x+2=3k/5, that lies in the interval [0,3] is

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MARKS Content Team · Accepted Answer

Correct answer: (B) 7/3. We have, ∫033x^2-4x+2dx=k ⇒k=x^3-2x^2+2x+c03 ⇒k=27-18+6=15. Again we have, 3x^2-4x+2=3k/5 ⇒3x^2-4x+2=(3·15)/5=9 ⇒3x^2-4x-7=0 ⇒3x^2-7x+3x-7=0 ⇒x+13x-7=0 ⇒x=-1 & 7/3

If $\int_{0}^{3} (3 x^{2} - 4 x + 2) d x = k$ , then a root of $3 x^{2} - 4 x + 2 = \frac{3 k}{5}$ , that lies in the interval $[0, 3]$ is

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Relevant Questions

If ∫033x2-4x+2dx=k, then a root of 3x2-4x+2=3k5, that lies in the interval [0,3] is

Solution

Relevant Questions

If $\int_{0}^{3} (3 x^{2} - 4 x + 2) d x = k$ , then a root of $3 x^{2} - 4 x + 2 = \frac{3 k}{5}$ , that lies in the interval $[0, 3]$ is