Identify the product obtained in the following reaction. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Br}+\mathrm{CH}_3 \mathrm{COOAg} \xrightarrow{\Delta} \mathrm{x}+\mathrm{AgBr}$

• A

  $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOCH}_3$
• Correct answer
  B

  $\mathrm{CH}_3 \mathrm{COOCH}_2 \mathrm{CH}_3$
• C

  $\mathrm{CH}_3 \mathrm{COOCH}_3$
• D

  $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOCH}_2 \mathrm{CH}_3$

Hence, the correct answer is option: 'B'.