Q149 / 200 · MHT CET - Medical 2026 (21 April Shift 1) · Chemistry
Identify the polymer from the following that is obtained by using one of the $\alpha$-amino acids.
- ANylon-6
- BPHBV
- Correct answerCNylon2- nylon6
- DBakelite
Solution
Nylon-2-nylon-6 is an alternating polyamide copolymer synthesized from glycine and aminocaproic acid.
Glycine ($H_2N-CH_2-COOH$) is an $\alpha$-amino acid, whereas aminocaproic acid ($H_2N-(CH_2)_5-COOH$) is an $\epsilon$-amino acid.
Nylon-6 is formed from caprolactam.
PHBV is formed from 3-hydroxybutanoic acid and 3-hydroxypentanoic acid.
Bakelite is formed from phenol and formaldehyde.
Thus, Nylon-2-nylon-6 is the polymer obtained by using an $\alpha$-amino acid.
Answer: Nylon2- nylon6
Glycine ($H_2N-CH_2-COOH$) is an $\alpha$-amino acid, whereas aminocaproic acid ($H_2N-(CH_2)_5-COOH$) is an $\epsilon$-amino acid.
Nylon-6 is formed from caprolactam.
PHBV is formed from 3-hydroxybutanoic acid and 3-hydroxypentanoic acid.
Bakelite is formed from phenol and formaldehyde.
Thus, Nylon-2-nylon-6 is the polymer obtained by using an $\alpha$-amino acid.
Answer: Nylon2- nylon6
Hence, the correct answer is option: 'C'.