Q4 / 90 · JEE Main 2021 (16 Mar Shift 2) · Chemistry

Identify the elements X and Y using the ionization energy values given below :

Ionization energy(kJ/mol)1st2ndX4954563Y7311450

  • Correct answer
    A
    X=Na;Y=Mg
  • B
    X=Mg;Y=F
  • C
    X=Mg;Y=Na
  • D
    X=F;Y=Mg

Solution

Na→Ne3s1IE1 is very low but IE2 is very high due to stable noble gas configuration of Na+.

Mg→Ne3s2IE1 and IE2→ Low

IE3 is very high.

Hence, the correct answer is option: 'A'.

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