Identify the element reduced in following reaction. $\mathrm{Cr}_2 \mathrm{O}_7^{2-}+14 \mathrm{H}^{+}+6 \mathrm{I}^{-} \longrightarrow 2 \mathrm{Cr}^{3+}+3 \mathrm{H}_2 \mathrm{O}+3 \mathrm{I}_2$

• Correct answer
  A

  Cr
• B

  H
• C

  0
• D

  I

Solution

In the following redox reaction, $I^{-}$is getting oxidized (change in O.S. from -1 to 0 ) and Cr is getting reduced (change in O.S. from +6 to +3 ).

Hence, the correct answer is option: 'A'.