Q1 / 180 · COMEDK 2025 (10 May Shift 3) · Chemistry

Identify the Carbonyl compound which will not be formed when hydration of Alkynes is carried out with dil. $\mathrm{H}_2 \mathrm{SO}_4 / \mathrm{Hg}^{2+}$ at 333 K . Acetone, Butanal, Ethanal, Butanone.

  • Correct answer
    A
    Butanal
  • B
    Butanone
  • C
    Acetone
  • D
    Ethanal

Solution

Hydration of alkynes in the presence of dil. $\mathrm{H}_{2}\mathrm{SO}_{4}$ and $\mathrm{Hg}^{2+}$ follows Markovnikov addition of water to the triple bond, forming an enol intermediate which tautomerizes to a carbonyl compound.

For ethyne ($HC \equiv CH$), hydration yields ethenol, which tautomerizes to ethanal ($CH_{3}CHO$).

For propyne ($CH_{3}C \equiv CH$), hydration yields prop-1-en-2-ol, which tautomerizes to acetone ($CH_{3}COCH_{3}$).

For but-1-yne ($CH_{3}CH_{2}C \equiv CH$), hydration yields but-1-en-2-ol, which tautomerizes to butanone ($CH_{3}COCH_{2}CH_{3}$).

For but-2-yne ($CH_{3}C \equiv CCH_{3}$), hydration yields but-2-en-2-ol, which tautomerizes to butanone ($CH_{3}COCH_{2}CH_{3}$).

Butanal ($CH_{3}CH_{2}CH_{2}CHO$) is an aldehyde with four carbon atoms. It would require the anti-Markovnikov addition of water to but-1-yne or the hydration of a terminal alkyne at the terminal carbon, which is not the product of the acid-catalyzed hydration of alkynes using $\mathrm{Hg}^{2+}$ catalyst. Therefore, butanal is not formed.

Answer: Butanal

Hence, the correct answer is option: 'A'.

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