Q11 / 150 · MHT CET 2026 (17 April Shift 2) · Chemistry

Identify oxidation number of Sulphur respectively in $\text{SO}_2$ and $\text{SO}_4^{2-}$ .

  • A
    $+6 , +4$
  • Correct answer
    B
    $+4, +6$
  • C
    $+4, +3$
  • D
    $+3, +4$

Solution

Let the oxidation number of Sulphur in $\text{SO}_2$ be $x$.

$x + 2(-2) = 0$

$x = +4$

Let the oxidation number of Sulphur in $\text{SO}_4^{2-}$ be $y$.

$y + 4(-2) = -2$

$y - 8 = -2$

$y = +6$

The oxidation numbers of Sulphur in $\text{SO}_2$ and $\text{SO}_4^{2-}$ are $+4$ and $+6$ respectively.

Answer: $+4, +6$

Hence, the correct answer is option: 'B'.

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