Q40 / 150 · MHT CET 2026 (18 April Shift 2) · Chemistry
Identify 'B' in the following reaction
Ethyl cyanide $\xrightarrow{\large{\text{H}_2\text{O}}} \text{A} \xrightarrow{\large{\text{H}_2\text{O / dil HCl}}} \text{B} + \text{NH}_3$
Ethyl cyanide $\xrightarrow{\large{\text{H}_2\text{O}}} \text{A} \xrightarrow{\large{\text{H}_2\text{O / dil HCl}}} \text{B} + \text{NH}_3$
- AEthanoic acid
- BEthanamide
- Correct answerCPropanoic acid
- DPropanamide
Solution
Ethyl cyanide is $\text{CH}_3\text{CH}_2\text{CN}$.
Partial hydrolysis of ethyl cyanide yields propanamide (A).
$\text{CH}_3\text{CH}_2\text{CN} \xrightarrow{\text{H}_2\text{O}} \text{CH}_3\text{CH}_2\text{CONH}_2$
Complete hydrolysis of propanamide in the presence of dilute $\text{HCl}$ yields propanoic acid (B) and ammonia.
$\text{CH}_3\text{CH}_2\text{CONH}_2 \xrightarrow{\text{H}_2\text{O} / \text{dil HCl}} \text{CH}_3\text{CH}_2\text{COOH} + \text{NH}_3$
Therefore, B is propanoic acid.
Answer: Propanoic acid
Partial hydrolysis of ethyl cyanide yields propanamide (A).
$\text{CH}_3\text{CH}_2\text{CN} \xrightarrow{\text{H}_2\text{O}} \text{CH}_3\text{CH}_2\text{CONH}_2$
Complete hydrolysis of propanamide in the presence of dilute $\text{HCl}$ yields propanoic acid (B) and ammonia.
$\text{CH}_3\text{CH}_2\text{CONH}_2 \xrightarrow{\text{H}_2\text{O} / \text{dil HCl}} \text{CH}_3\text{CH}_2\text{COOH} + \text{NH}_3$
Therefore, B is propanoic acid.
Answer: Propanoic acid
Hence, the correct answer is option: 'C'.