Q40 / 160 · TS EAMCET 2019 (03 May Shift 1) · Chemistry
Identify $X, Y$ and $Z$ respectively in the following reaction sequence :
Acetic acid $\underset{\substack{\text { (iii) } \mathrm{C}_6 \mathrm{H}_5 \mathrm{SO}_2 \mathrm{Cl} \\ \text { Pyridine } / 343 \mathrm{~K}}}{\stackrel{\left.\text { (i) } \mathrm{NH}_3, \mathrm{ii}\right)}{\longrightarrow}} X+Y+Z$
- A$\mathrm{C}_6 \mathrm{H}_5 \mathrm{SO}_3 \mathrm{H}, \mathrm{CH}_3 \mathrm{NC}, \mathrm{HCl}$
- Correct answerB

- C$\mathrm{C}_6 \mathrm{H}_5 \mathrm{SO}_3 \mathrm{H}, \mathrm{CH}_3 \mathrm{CN}, \mathrm{HCl}$
- D$\mathrm{C}_6 \mathrm{H}_5 \mathrm{SO}_2 \mathrm{Cl}, \mathrm{CH}_3 \mathrm{NC}, \mathrm{H}_2 \mathrm{O}$
Solution

$$ \text { Hence, answer (2) is the correct option. } $$
Hence, the correct answer is option: 'B'.