Q16 / 160 · AP EAMCET 2022 (06 Jul Shift 2) · Chemistry

Identify $A, B, C$ and $D$ in the reactions (I) $x \mathrm{Cl}_2+y \mathrm{NaOH} \longrightarrow A+B+\mathrm{H}_2 \mathrm{O}(l)$ (Cold, dil) (II) $x \mathrm{Cl}_2+y \mathrm{NaOH} \longrightarrow \mathrm{C}+\mathrm{D}+\mathrm{H}_2 \mathrm{O}(l)$ (Hot, conc.)

  • A
    $\mathrm{NaCl}, \mathrm{HCl}, \mathrm{NaOCl}, \mathrm{NaClO}_3$
  • Correct answer
    B
    $\mathrm{NaCl}, \mathrm{NaOCl}, \mathrm{NaCl}, \mathrm{NaClO}_3$
  • C
    $\mathrm{NaCl}, \mathrm{NaOCl}_3, \mathrm{NaCl}, \mathrm{NaOCl}$
  • D
    $\mathrm{NaOCl}, \mathrm{Na}_2 \mathrm{O}, \mathrm{NaOCl}, \mathrm{NaO}_2$

Solution

When chlorine reacts with $\mathrm{NaOH}$, different products are formed depending upon the temperature and concentration of $\mathrm{NaOH}$. $$ \begin{aligned} & \mathrm{Cl}_2+2 \mathrm{NaOH} \longrightarrow \mathrm{NaCl}+\mathrm{NaOCl}+\mathrm{H}_2 \mathrm{O} \\ & \text { (Cold and dil.) } \\ & 3 \mathrm{Cl}_2+6 \mathrm{NaOH} \longrightarrow 5 \mathrm{NaCl}+\mathrm{NaClO}_3+3 \mathrm{H}_2 \mathrm{O} \\ & \end{aligned} $$ (Hot and conc.) So, $A=\mathrm{NaCl}, B=\mathrm{NaOCl}, C=\mathrm{NaCl}, D=\mathrm{NaClO}_3$

Hence, the correct answer is option: 'B'.

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