Identify $\mathrm{X}$ and $\mathrm{Y}$ in the following reaction $\mathrm{CH}_2=\mathrm{CH}_2 \underset{\text { (ii) } \mathrm{Y}}{\longrightarrow} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{I}$

• Correct answer
  A

  $\mathrm{HBr}, \mathrm{NaI} /$ dry $\mathrm{CH}_3 \mathrm{COCH}_3$
• B

  $\mathrm{HBr}, \mathrm{I}_2 / \mathrm{dry} \mathrm{CH}_3 \mathrm{COCH}_3$
• C

  $\mathrm{Br}_2, \mathrm{NaI} / \mathrm{dry} \mathrm{CH}_3 \mathrm{COCH}_3$
• D

  $\mathrm{Br}_2, \mathrm{I}_2 /$ dry $\mathrm{CH}_3 \mathrm{COCH}_3$

Hence, the correct answer is option: 'A'.