Q28 / 200 · Manipal (MET) 2013 · Chemistry

Figure
I. Formation of $A$ has proceeded with racemisation. II. Formation of $B$ has proceeded with inversion. Select the correct statement. Select the correct statement.

  • Correct answer
    A
    I and II
  • B
    Only I
  • C
    Only III
  • D
    None of these

Solution

$\mathrm{S}_{\mathrm{N}} 1$ reaction proceed through formation of carbocation which can form a pair of enantiomers. Thus, recemisation takes place (statement I). $\mathrm{S}_{\mathrm{N}} 2$ reaction takes place forming pantavalent intermediate which loses $\mathrm{Cl}^{-}$giving inverted alcohol. (Statement II ) Hence, statements I and II both are correct.

Hence, the correct answer is option: 'A'.

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