Q5 / 90 · KVPY 2013 (SB/SX) · Chemistry
Hydrolysis of $\mathrm{BCl}_{3}$ gives $\mathrm{X}$ which on treatment with sodium carbonate produces $\mathrm{Y}, \mathrm{X}$ and $\mathrm{Y}$, respectively, are
- A$\mathrm{H}_{3} \mathrm{BO}_{3}$ and $\mathrm{NaBO}_{2}$
- Correct answerB$\mathrm{H}_{3} \mathrm{BO}_{3}$ and $\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{7}$
- C$\mathrm{B}_{2}^{\circ} \mathrm{O}_{3}$ and $\mathrm{NaBO}_{2}$
- D$\mathrm{B}_{2} \mathrm{O}_{3}$ and $\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{7}$
Solution
$\mathrm{BCl}_{3}+3 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{H}_{3} \mathrm{BO}_{3}+3 \mathrm{HCl}$
$4 \mathrm{H}_{3} \mathrm{BO}_{3}+\mathrm{Na}_{2} \mathrm{CO}_{3} \longrightarrow \mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{7}+\mathrm{CO}_{2}+6 \mathrm{H}_{2} \mathrm{O}$
Hence, the correct answer is option: 'B'.