Hybridisation of the negative carbons in (1) and (2) are

• A

  $\mathrm{sp}^2$ and $\mathrm{sp}^3$
• Correct answer
  B

  $\mathrm{sp}^3$ and $\mathrm{sp}^2$
• C

  both $\mathrm{sp}^2$
• D

  None of the above

Solution

Probable structures are:

Hence, the correct answer is option: 'B'.