How much solid oxalic acid (Molecular weight 126 ) has to be weighed to prepare 100 ~mL exactly 0.1 (N) oxalic acid solution in water?

Correct answer: (C) 0.63 ~g. n_eq=N × V(L) =(0.1) (100/1000 )=0.01 weight = no. of eq (n_e q ) × Equivalent mass =0.01 × 126/2=0.63 ~g

Q28 / 155 · WBJEE 2022 · Chemistry

How much solid oxalic acid (Molecular weight 126 ) has to be weighed to prepare $100 \mathrm{~mL}$ exactly $0.1$ (N) oxalic acid solution in water?

A
$1.26 \mathrm{~g}$
B
$0.126 \mathrm{~g}$
Correct answer
C
$0.63 \mathrm{~g}$
D
$0.063 \mathrm{~g}$

Solution

$\mathrm{n}_{\mathrm{eq}}=\mathrm{N} \times \mathrm{V}(\mathrm{L})$ $=(0.1)\left(\frac{100}{1000}\right)=0.01$ weight $=$ no. of eq $\left(n_{e q}\right) \times$ Equivalent mass $=0.01 \times \frac{126}{2}=0.63 \mathrm{~g}$

Hence, the correct answer is option: 'C'.

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