Q70 / 160 · JIPMER 2005 · Chemistry

How much chlorine will be liberated on passing one ampere current for 30 min through NaCl solution?

  • A
    0.66 mole
  • B
    0.33 mole
  • Correct answer
    C
    0.66 g
  • D
    0.33 g

Solution

According to Faraday's law $\begin{aligned} & \frac{w}{E}=\frac{i t}{96500} \\ & \text { or } \quad \frac{w}{35.5}=\frac{1 \times 30 \times 60}{96500} \\ & \Rightarrow \quad=0.662 \mathrm{~g} \\ & \end{aligned}$ so, 0.662 g chlorine is liberated.

Hence, the correct answer is option: 'C'.

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