Q102 / 200 · MHT CET - Medical 2026 (26 April Shift 1) · Chemistry
How many total number of s and p electrons are respectively present in $\text{Cl}^-$ ?
- A$6$ and $11$
- Correct answerB$6$ and $12$
- C$2$ and $7$
- D$11$ and $6$
Solution
The atomic number of Chlorine ($\text{Cl}$) is $17$.
The $\text{Cl}^{-}$ ion has gained one electron, making the total number of electrons $17 + 1 = 18$.
The electronic configuration of $\text{Cl}^{-}$ is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}$.
Total number of s electrons $= 2 + 2 + 2 = 6$.
Total number of p electrons $= 6 + 6 = 12$.
Answer: $6$ and $12$
The $\text{Cl}^{-}$ ion has gained one electron, making the total number of electrons $17 + 1 = 18$.
The electronic configuration of $\text{Cl}^{-}$ is $1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6}$.
Total number of s electrons $= 2 + 2 + 2 = 6$.
Total number of p electrons $= 6 + 6 = 12$.
Answer: $6$ and $12$
Hence, the correct answer is option: 'B'.